Given a circle with measures of (C, d, and r) and a circle with measures of (C' ,d' , and r'). what is C' if d/d'=.25 and C=6?
Accepted Solution
A:
Answer: The value of c' is 24Step-by-step explanation:Given as for circle : C = 6 And [tex]\frac{d}{d'}[/tex] = .25 For circle first The Circumference of circle = CDiameter of circle = dRadius of circle = r So , circumference of circle = 2 [tex]\pi[/tex] rFor circle second The Circumference of circle = C'Diameter of circle = d'Radius of circle = r' So , circumference of circle = 2 [tex]\pi[/tex] r'Now, [tex]\frac{c}{c'}[/tex] = [tex]\frac{2 \pi r}{2 \pi r'}[/tex]Or, ∵ Diameter = 2 × RadiusSo, [tex]\frac{c}{c'}[/tex] = [tex]\frac{2 \pi d}{2 \pi d'}[/tex]Or, [tex]\frac{6}{c'}[/tex] = [tex]\frac{2 \pi d}{2 \pi d'}[/tex]So, [tex]\frac{6}{c'}[/tex] = [tex]\frac{25}{100}[/tex] ∴ c' = [tex]\frac{6\times 100}{25}[/tex] = 24 Hence The value of c' is 24 Answer