Given a circle with measures of (C, d, and r) and a circle with measures of (C' ,d' , and r'). what is C' if d/d'=.25 and C=6?​

Answer: The value of c' is 24Step-by-step explanation:Given as for circle : C =  6  And   [tex]\frac{d}{d'}[/tex] = .25 For circle first The Circumference of circle = CDiameter   of circle = dRadius of circle  = r So , circumference of circle = 2 [tex]\pi[/tex] rFor circle second  The Circumference of circle = C'Diameter   of circle = d'Radius of circle  = r' So , circumference of circle = 2 [tex]\pi[/tex] r'Now, [tex]\frac{c}{c'}[/tex] = [tex]\frac{2 \pi  r}{2 \pi  r'}[/tex]Or,   ∵  Diameter = 2 × RadiusSo, [tex]\frac{c}{c'}[/tex] = [tex]\frac{2 \pi  d}{2 \pi  d'}[/tex]Or, [tex]\frac{6}{c'}[/tex] = [tex]\frac{2 \pi  d}{2 \pi  d'}[/tex]So,   [tex]\frac{6}{c'}[/tex] =  [tex]\frac{25}{100}[/tex] ∴   c' = [tex]\frac{6\times 100}{25}[/tex] = 24 Hence  The value of c' is 24     Answer